)]}'
{"specs/in_progress/global_ec_cluster.rst":[{"author":{"_account_id":11317,"name":"Eran Rom","email":"eran@itsonlyme.name","username":"eranr"},"change_message_id":"a24e0ed7cc75e1a6f3b6c2399157bcc01a1327d0","unresolved":false,"context_lines":[{"line_number":103,"context_line":"- \"no duplication\" \u003c \"with duplication\" \u003c \"more unique parities\""},{"line_number":104,"context_line":""},{"line_number":105,"context_line":"In future work, we can find a way to tie a fragment index to a region,"},{"line_number":106,"context_line":"something like \"1st subset should be in 1st Region and 2nd subset"},{"line_number":107,"context_line":"should be ...\" but so far this is beyond this spec."},{"line_number":108,"context_line":""},{"line_number":109,"context_line":"Alternatives"}],"source_content_type":"text/x-rst","patch_set":1,"id":"ba15a1d1_a4adab9c","line":106,"updated":"2015-10-11 12:49:50.000000000","message":"So If I get this right implementation-wise duplicating all fragments is totally different then duplicating only part of the fragments. otherwise, one could do e.g. 10:4 and duplicate only 10 to the second region.","commit_id":"cdfa7b2ec504f7336c970c7d06ac8f750cb9e147"},{"author":{"_account_id":4608,"name":"Kota Tsuyuzaki","email":"bloodeagle40234@gmail.com","username":"tsuyuzaki-kota"},"change_message_id":"d3cd3eb6248c1bce6707463d181a7540ad17c25c","unresolved":false,"context_lines":[{"line_number":103,"context_line":"- \"no duplication\" \u003c \"with duplication\" \u003c \"more unique parities\""},{"line_number":104,"context_line":""},{"line_number":105,"context_line":"In future work, we can find a way to tie a fragment index to a region,"},{"line_number":106,"context_line":"something like \"1st subset should be in 1st Region and 2nd subset"},{"line_number":107,"context_line":"should be ...\" but so far this is beyond this spec."},{"line_number":108,"context_line":""},{"line_number":109,"context_line":"Alternatives"}],"source_content_type":"text/x-rst","patch_set":1,"id":"3a29b11f_e13ebfb7","line":106,"in_reply_to":"ba15a1d1_a4adab9c","updated":"2015-10-19 08:30:33.000000000","message":"Exactly. In my idea, we don\u0027t have a way to allow to duplicate only part of the fragments. i.e. always swift must have a ring consists of a replica number that equals to or a multiple of a number of fragments.\n\nAnyways, we should consider how to maintain the ring consistency with this feature. You asked good point, thanks.","commit_id":"cdfa7b2ec504f7336c970c7d06ac8f750cb9e147"}]}